2sin^2(3x)+sin^2(6x)=2

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Solution for 2sin^2(3x)+sin^2(6x)=2 equation:


Simplifying
2sin2(3x) + sin2(6x) = 2

Remove parenthesis around (3x)
2in2s * 3x + sin2(6x) = 2

Reorder the terms for easier multiplication:
2 * 3in2s * x + sin2(6x) = 2

Multiply 2 * 3
6in2s * x + sin2(6x) = 2

Multiply in2s * x
6in2sx + sin2(6x) = 2

Remove parenthesis around (6x)
6in2sx + in2s * 6x = 2

Reorder the terms for easier multiplication:
6in2sx + 6in2s * x = 2

Multiply in2s * x
6in2sx + 6in2sx = 2

Combine like terms: 6in2sx + 6in2sx = 12in2sx
12in2sx = 2

Solving
12in2sx = 2

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Divide each side by '12n2sx'.
i = 0.1666666667n-2s-1x-1

Simplifying
i = 0.1666666667n-2s-1x-1

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